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Acapulco (Mexico) (AFP) – Alexander Zverev was victorious over Jenson Brooksby in Acapulco early Tuesday morning in the final final of a professional tennis match.
The Olympic champion saved two match points before wrapping up a 3-6, 7-6 (12/10), 6-2 victory at 04:54 local time (10:54 GMT).
The tie in the first round of the ATP event lasted three hours and 19 minutes, the third game on Monday’s schedule to break the three-hour mark.
The last previous finish was a 2008 Australian Open match between Lleyton Hewitt and Marcos Baghdatis which ended at 4:34am.
Zverev and Brooksby were still playing as a doubles match, scheduled for Tuesday, had already ended in Dubai, 10 hours ahead of Acapulco.
American Brooksby won the first set but saw two match points come and go in the second set tie-break.
Zverev finally forced a decider on his fifth set point, winning a set that lasted 111 minutes.
Despite appearing to be suffering from a cramp, the German world number three managed to find two breaks of serve in the third set.
Zverev will face compatriot Peter Gojowczyk in the round of 16.
Later on Tuesday, Rafael Nadal will play for the first time since his record triumph at the Australian Open when he takes on Denis Kudla.
Daniil Medvedev, chasing Novak Djokovic’s world number one spot, takes on Benoit Paire.
© 2022 AFP
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